To understand the HyperGeometric distribution, consider a set of \(r\) objects, of which \(m\) are of the type I and \(n\) are of the type II. A sample with size \(k\) (\(k<r\)) with no replacement is randomly chosen. The number of observed type I elements observed in this sample is set to be our random variable \(X\).
dist_hypergeometric(m, n, k)
We recommend reading this documentation on https://pkg.mitchelloharawild.com/distributional/, where the math will render nicely.
In the following, let \(X\) be a HyperGeometric random variable with
success probability p
= \(p = m/(m+n)\).
Support: \(x \in { \{\max{(0, k-n)}, \dots, \min{(k,m)}}\}\)
Mean: \(\frac{km}{n+m} = kp\)
Variance: \(\frac{km(n)(n+m-k)}{(n+m)^2 (n+m-1)} = kp(1-p)(1 - \frac{k-1}{m+n-1})\)
Probability mass function (p.m.f):
$$ P(X = x) = \frac{{m \choose x}{n \choose k-x}}{{m+n \choose k}} $$
Cumulative distribution function (c.d.f):
$$ P(X \le k) \approx \Phi\Big(\frac{x - kp}{\sqrt{kp(1-p)}}\Big) $$
dist <- dist_hypergeometric(m = rep(500, 3), n = c(50, 60, 70), k = c(100, 200, 300))
dist
#> <distribution[3]>
#> [1] Hypergeometric(500, 50, 100) Hypergeometric(500, 60, 200)
#> [3] Hypergeometric(500, 70, 300)
mean(dist)
#> [1] 90.90909 178.57143 263.15789
variance(dist)
#> [1] 6.77415 12.32157 15.33526
skewness(dist)
#> Warning: NAs produced by integer overflow
#> Warning: NAs produced by integer overflow
#> [1] -0.2007751 NA NA
kurtosis(dist)
#> Warning: NAs produced by integer overflow
#> Warning: NAs produced by integer overflow
#> [1] 2.965375e-15 NA NA
generate(dist, 10)
#> [[1]]
#> [1] 88 91 91 90 92 93 92 88 89 92
#>
#> [[2]]
#> [1] 184 176 184 180 178 173 179 172 179 183
#>
#> [[3]]
#> [1] 263 267 266 260 261 266 266 261 267 259
#>
density(dist, 2)
#> [1] 0 0 0
density(dist, 2, log = TRUE)
#> [1] -Inf -Inf -Inf
cdf(dist, 4)
#> [1] 0 0 0
quantile(dist, 0.7)
#> [1] 92 180 265